---
title: Diamagnetism and Paramagnetism
module: Magnetism in Solids
moduleNumber: 9
lessonNumber: 1
order: 901
summary: >
  Every solid responds to a magnetic field. Filled shells give a small negative
  diamagnetic susceptibility from induced Larmor currents; localized moments give
  a positive Curie paramagnetism described by the Brillouin function, with the
  ground-state moment fixed by Hund's rules. The conduction electrons add a
  temperature-independent Pauli paramagnetism from the thermal shell near the
  Fermi surface, partly cancelled by Landau diamagnetism of their orbital motion.
topics: [Magnetism in Solids]
draft: false
sources:
  - book: Kittel
    ref: "Ch. 11 — Diamagnetism and Paramagnetism"
  - book: Ashcroft & Mermin
    ref: "Ch. 31 — Diamagnetism and Paramagnetism"
  - book: Hook & Hall
    ref: "Ch. 7 — Magnetic Properties of Materials"
---

A solid placed in an applied field $\vec H$ acquires a magnetization $\vec M$, the
magnetic moment per unit volume. For fields well below saturation the response is
linear, and the **volume susceptibility**

$$
\chi = \frac{M}{H}
$$

is a dimensionless material constant (SI). The flux density inside is $\vec B =
\mu_0(\vec H + \vec M) = \mu_0(1+\chi)\vec H$. The sign and size of $\chi$ sort
non-ordered matter into two classes. **Diamagnets** have $\chi < 0$, of order
$-10^{-5}$, and are repelled by a field; the response comes from the induced
currents of otherwise moment-free filled shells. **Paramagnets** have $\chi > 0$,
between $10^{-5}$ and $10^{-2}$, and are drawn into a field; the response comes
from permanent atomic moments (or conduction electrons) aligning with it. Ordered
magnets — ferromagnets and antiferromagnets — are the subject of the following
lessons; here the moments are independent.

The natural unit of atomic moment is the **Bohr magneton**

$$
\mu_B = \frac{e\hbar}{2m_e} = 9.274\times10^{-24}\ \text{J T}^{-1},
$$

the moment of one electron's orbital angular momentum quantum.[^codata] An energy
$\mu_B B$ at a laboratory field of $1\ \text{T}$ is $9.3\times10^{-24}\ \text{J}$,
or $0.67\ \text{K}$ in temperature units — small against $k_B T$ at room
temperature, which is why paramagnetic alignment is weak and why the linear
regime is the usual one.

## Larmor diamagnetism of closed shells

An atom with all shells filled has no net spin or orbital angular momentum and no
permanent moment. It still responds to a field, because switching the field on
induces electronic currents that, by Lenz's law, oppose the change. This is the
**Langevin–Larmor** diamagnetism.

Consider one electron in an atom subjected to a field $\vec B$ along $\hat z$. The
classical effect of the field is to superimpose on the electron's motion a uniform
precession about $\hat z$ at the **Larmor frequency**

$$
\omega_L = \frac{eB}{2m_e}.
$$

This precession is a circulating current $I = -\,e\,\omega_L/2\pi$ enclosing the
projected area of the orbit. A current loop of area $A$ carries moment $IA$, so
each electron acquires an induced moment

$$
\mu = -\frac{e^2 B}{4 m_e}\langle \rho^2\rangle,
\qquad \langle \rho^2\rangle = \langle x^2 + y^2\rangle,
$$

directed opposite to $\vec B$. For a spherically symmetric shell $\langle x^2\rangle
= \langle y^2\rangle = \langle z^2\rangle$, so $\langle\rho^2\rangle =
\tfrac{2}{3}\langle r^2\rangle$. Summing over the $Z$ electrons of each atom and
multiplying by the number density $n$ of atoms gives the diamagnetic
susceptibility

$$
\chi_{\text{dia}} = -\frac{\mu_0 n e^2}{6 m_e}\sum_{i=1}^{Z}\langle r_i^2\rangle.
$$

The result is negative, temperature-independent, and small: with $\langle r^2\rangle
\sim (0.1\ \text{nm})^2$ and $n \sim 5\times10^{28}\ \text{m}^{-3}$ it gives $\chi
\sim -10^{-5}$, matching the inert gases and simple ionic solids. The same
$\langle r^2\rangle$ that sets an ion's size sets its diamagnetism, so the two
correlate across the periodic table.

$$
% caption: Switching on B induces a Larmor circulation whose moment opposes the
% field (Lenz's law); the induced current loop gives every filled shell a small
% negative susceptibility.
\begin{tikzpicture}[scale=1.0, >=stealth, font=\footnotesize]
  \definecolor{acc}{HTML}{4A6FA5}
  % field lines up
  \foreach \x in {-2.4,-1.6,-0.8}{
    \draw[black, ->] (\x,-1.7) -- (\x,1.9);
  }
  \node[black, anchor=south] at (-1.6,1.9) {applied $B$};
  % nucleus and orbit
  \fill[black] (1.6,0) circle (2pt);
  \draw[acc, very thick] (1.6,0) ellipse (1.15 and 0.55);
  % current direction arrows on the loop
  \draw[acc, ->, very thick] (2.75,0.02) -- (2.75,-0.05);
  \draw[acc, ->, very thick] (0.45,-0.02) -- (0.45,0.05);
  \node[acc, anchor=west] at (2.85,0.35) {induced current};
  % induced moment down
  \draw[acc, ->, very thick] (1.6,0) -- (1.6,-1.5);
  \node[acc, anchor=north] at (1.6,-1.55) {moment opposes $B$};
\end{tikzpicture}
$$

## Curie paramagnetism of localized moments

An atom or ion with an incomplete shell carries a permanent moment $\vec\mu = -g
\mu_B \vec J/\hbar$, where $\vec J$ is the total angular momentum and $g$ the Landé
factor. In a field $\vec B = B\hat z$ the $2J+1$ orientations of $\vec J$ have
energies

$$
E_{m} = m\, g\mu_B B, \qquad m = -J, -J+1, \dots, J.
$$

At temperature $T$ the states are populated by Boltzmann weights, and the mean
moment along the field follows from the partition function $Z = \sum_m
e^{-E_m/k_B T}$. Writing $x = g\mu_B J B/k_B T$, the sum is a finite geometric
series, and the thermal-average moment per ion is

$$
\langle \mu_z\rangle = g\mu_B J\, B_J(x),
$$

where the **Brillouin function** is

$$
B_J(x) = \frac{2J+1}{2J}\coth\!\left(\frac{2J+1}{2J}x\right)
        - \frac{1}{2J}\coth\!\left(\frac{x}{2J}\right).
$$

The magnetization of $n$ ions per unit volume is $M = n g\mu_B J\, B_J(x)$. Two
limits fix its shape.

At large $x$ (strong field or low temperature) $B_J \to 1$ and the moments
saturate at $M_s = n g\mu_B J$: every ion points along the field. At small $x$
(the usual laboratory case) $\coth u \approx 1/u + u/3$ gives

$$
B_J(x) \approx \frac{J+1}{3J}\,x,
$$

so the magnetization is linear in $B$ and the susceptibility follows the **Curie
law**

$$
\chi = \frac{\mu_0 n\, p^2 \mu_B^2}{3 k_B T} \equiv \frac{C}{T},
\qquad p = g\sqrt{J(J+1)}.
$$

The dimensionless $p$ is the **effective moment number**; $C$ is the Curie
constant. The $1/T$ dependence is the fingerprint of independent moments: thermal
agitation randomizes them, and the aligning tendency of a fixed field wins in
inverse proportion to temperature. Plotting $1/\chi$ against $T$ gives a straight
line through the origin whose slope measures $p$.

$$
% caption: The Brillouin magnetization M/M_s versus B/T saturates at unity; larger
% J rises more steeply and the classical Langevin limit (J to infinity) is the
% smoothest curve. All share the same small-field Curie slope.
\begin{tikzpicture}[scale=1.0, >=stealth, font=\footnotesize]
  \definecolor{acc}{HTML}{4A6FA5}
  \draw[->, black] (0,0) -- (6.6,0) node[below right] {$\frac{B}{T}$};
  \draw[->, black] (0,0) -- (0,3.6) node[left] {magnetization};
  \draw[black, dashed] (0,3.0) -- (6.4,3.0);
  \node[black, anchor=south east] at (6.4,3.0) {saturation};
  % J = 5/2 : steepest saturating rise
  \draw[black, thick, domain=0:6.3, samples=120, variable=\x]
    plot ({\x},{3.0*(1.1*\x)/sqrt(1 + 1.21*\x*\x)});
  \node[black, anchor=west] at (2.0,2.9) {$J=\frac{5}{2}$};
  % J = 1/2 : intermediate
  \draw[acc, very thick, domain=0:6.3, samples=120, variable=\x]
    plot ({\x},{3.0*(0.62*\x)/sqrt(1 + 0.3844*\x*\x)});
  \node[acc, anchor=west] at (4.3,2.35) {$J=\frac{1}{2}$};
  % classical Langevin: smoothest, slowest approach
  \draw[black, thick, densely dotted, domain=0:6.3, samples=120, variable=\x]
    plot ({\x},{3.0*(0.34*\x)/sqrt(1 + 0.1156*\x*\x)});
  \node[black, anchor=north west] at (3.2,1.05) {classical};
\end{tikzpicture}
$$

The classical case is recovered as $J\to\infty$ with $g\mu_B J = \mu$ fixed. The
Brillouin function then becomes the **Langevin function**

$$
L(x) = \coth x - \frac{1}{x},
$$

the result for a freely rotating classical dipole. That Langevin's classical
theory and the quantum Brillouin theory agree at small field — both give a $1/T$
law — is why paramagnetism was understood before quantum mechanics, and why the
measured $p$ (not the classical value) was one of the early confirmations of
angular-momentum quantization.

$$
% caption: The Curie law plotted as inverse susceptibility against temperature is
% a straight line through the origin; its slope is the reciprocal Curie constant
% and fixes the effective moment number p.
\begin{tikzpicture}[scale=1.0, >=stealth, font=\footnotesize]
  \definecolor{acc}{HTML}{4A6FA5}
  \draw[->, black] (0,0) -- (6.4,0) node[below right] {temperature};
  \draw[->, black] (0,0) -- (0,3.8) node[left] {inverse susceptibility};
  \draw[acc, very thick] (0,0) -- (5.8,3.4);
  \node[acc, anchor=west] at (4.5,2.35) {slope $=\frac{1}{C}$};
  \fill[black] (2.0,1.17) circle (1.6pt);
  \fill[black] (3.5,2.05) circle (1.6pt);
  \fill[black] (5.0,2.93) circle (1.6pt);
\end{tikzpicture}
$$

## Hund's rules and the ground-state moment

To predict $p$ for a given ion the ground-state values of $S$, $L$, and $J$ of the
partly filled shell are needed. For the free ion these follow from **Hund's
rules**, which minimize the electrostatic and spin–orbit energy of the
open-shell electrons:

- **Maximum spin.** Arrange the electron spins to maximize the total $S =
  \sum m_s$ allowed by the exclusion principle. Parallel spins keep electrons in
  different orbitals, lowering their mutual Coulomb repulsion.
- **Maximum orbital angular momentum.** Consistent with that $S$, maximize $L =
  \lvert\sum m_\ell\rvert$. Electrons orbiting the same way avoid one another and
  again lower the repulsion.
- **Spin–orbit coupling.** Set $J = \lvert L - S\rvert$ for a shell less than half
  full, and $J = L + S$ for a shell more than half full. A half-filled shell has
  $L = 0$ and $J = S$.

For example, the $\text{Fe}^{3+}$ ion has a half-filled $3d^5$ shell: five
parallel spins give $S = \tfrac{5}{2}$, the orbital contributions cancel to $L =
0$, and $J = S = \tfrac{5}{2}$ with $g = 2$. The predicted $p = g\sqrt{J(J+1)} =
5.9$ matches the measured value for iron-group salts. The rare-earth ions, whose
$4f$ shells are buried inside the closed $5s5p$ shells and so nearly free, agree
with the full $p = g\sqrt{J(J+1)}$ across the series.

$$
% caption: Hund-rule filling of a d-shell (five orbitals): the first five
% electrons go in parallel to maximize spin before any orbital is doubly occupied.
\begin{tikzpicture}[scale=1.0, >=stealth, font=\footnotesize]
  \definecolor{acc}{HTML}{4A6FA5}
  \foreach \i in {0,1,2,3,4}{
    \draw[black] (\i*1.05,0) rectangle (\i*1.05+0.7,0.7);
    % up spin in each box
    \draw[acc, very thick, ->] (\i*1.05+0.35,0.12) -- (\i*1.05+0.35,0.58);
  }
  \node[black, anchor=north] at (2.1,-0.15) {all spins parallel: $S=\frac{5}{2}$, $L=0$};
\end{tikzpicture}
$$

Two caveats matter in solids. For the iron-group ions the crystal field of the
neighboring atoms is stronger than the spin–orbit coupling and **quenches** the
orbital angular momentum, so $L$ is effectively zero and only the spin survives;
the measured $p$ agrees with $g = 2$, $J = S$ rather than with the free-ion $J$.
The rare earths, shielded from the crystal field, keep their free-ion $J$.

## Pauli paramagnetism of the conduction electrons

A metal's conduction electrons each carry a spin moment $\mu_B$, so a naive Curie
estimate would predict a large $1/T$ paramagnetism. The measured spin
susceptibility of the alkali metals is instead small and nearly
temperature-independent. The exclusion principle is again the reason: only the
electrons within about $k_B T$ of the Fermi energy can flip their spins into
empty states, a fraction $T/T_F$ of the whole.

In a field $\vec B$ the spin-up and spin-down bands shift in energy by $\mp\mu_B
B$. Electrons transfer from the higher (spin-antiparallel) band to the lower until
the Fermi levels align, producing an excess $\Delta n = g(E_F)\mu_B B$ of aligned
spins, where $g(E_F)$ is the density of states at the Fermi energy (both spins).
The magnetization $M = \mu_B\Delta n$ gives the **Pauli susceptibility**

$$
\chi_{\text{Pauli}} = \mu_0\,\mu_B^2\, g(E_F).
$$

Using the free-electron $g(E_F) = 3n/2E_F = 3n/2k_B T_F$,

$$
\chi_{\text{Pauli}} = \frac{3 n \mu_0 \mu_B^2}{2 k_B T_F},
$$

which is the Curie result with $T$ replaced by the far larger Fermi temperature
$T_F \sim 10^4\ \text{K}$ — smaller by two orders of magnitude, and independent of
$T$ because the excited shell width and the level spacing both scale with $T$ and
cancel.

$$
% caption: In a field the spin-up density of states drops by mu_B B and spin-down
% rises; electrons refill to a common Fermi level, leaving a net excess of aligned
% spins proportional to g(E_F). Only the shaded Fermi shell participates.
\begin{tikzpicture}[scale=1.0, >=stealth, font=\footnotesize]
  \definecolor{acc}{HTML}{4A6FA5}
  % spin-up (left, shifted down): parabola opening right, filled to E_F
  \begin{scope}
    \draw[black, ->] (0,0) -- (0,3.4) node[left] {energy};
    \draw[acc, very thick, domain=0:2.9, samples=60, variable=\y]
      plot ({-1.1*sqrt(\y+0.3)},{\y});
    \fill[acc!12] plot[domain=0:2.6, samples=60, variable=\y] ({-1.1*sqrt(\y+0.3)},{\y}) -- (0,2.6) -- (0,0) -- cycle;
    \draw[black, dashed] (-1.9,2.6) -- (0,2.6);
    \node[acc, anchor=north] at (-1.1,-0.15) {spin up};
  \end{scope}
  % spin-down (right, shifted up)
  \begin{scope}
    \draw[black, very thick, domain=0:2.9, samples=60, variable=\y]
      plot ({1.1*sqrt(\y+0.3)},{\y});
    \draw[black, dashed] (0,2.2) -- (1.9,2.2);
    \node[black, anchor=north] at (1.1,-0.15) {spin down};
  \end{scope}
  \node[black, anchor=west] at (2.0,2.6) {common $E_F$};
\end{tikzpicture}
$$

The orbital motion of the same conduction electrons, quantized into Landau levels
by the field, adds a diamagnetic contribution. For free electrons this **Landau
diamagnetism** is exactly one-third of the Pauli term with the opposite sign,

$$
\chi_{\text{Landau}} = -\tfrac{1}{3}\,\chi_{\text{Pauli}}
\quad(\text{free electrons}),
$$

so the net conduction-electron susceptibility is $\tfrac{2}{3}\chi_{\text{Pauli}}$
and still paramagnetic. In a real band the ratio changes because the orbital
motion feels the band effective mass $m^\ast$ while the spin feels the bare mass;
where $m^\ast$ is small (as in bismuth) the Landau term can dominate and the metal
is net diamagnetic.

The three responses — closed-shell diamagnetism, local-moment Curie paramagnetism,
and the conduction-electron Pauli and Landau terms — coexist in any real solid,
and their signs and temperature dependences let an experiment separate them. Where
the local moments interact strongly enough to order, the independent-moment
picture breaks down; the [exchange interaction](/condensed-matter/magnetism/exchange-and-ferromagnetism)
that drives that ordering is the next lesson.

| Mechanism | Sign of $\chi$ | Size | $T$-dependence |
| --- | --- | --- | --- |
| Larmor (closed shell) | $\chi < 0$ | $\sim 10^{-5}$ | independent |
| Curie (local moments) | $\chi > 0$ | $10^{-3}$–$10^{-5}$ | $\propto 1/T$ |
| Pauli (conduction spin) | $\chi > 0$ | $\sim 10^{-6}$ | independent |
| Landau (conduction orbit) | $\chi < 0$ | $\tfrac{1}{3}$ of Pauli | independent |

[^codata]: CODATA / NIST recommended value of the Bohr magneton, $\mu_B =
9.2740100783\times10^{-24}\ \text{J T}^{-1}$: [physics.nist.gov](https://physics.nist.gov/cgi-bin/cuu/Value?mub).
