---
title: The Semi-Empirical Mass Formula and the Valley of Stability
module: Nuclear Properties
moduleNumber: 1
lessonNumber: 4
order: 104
summary: >
  Five physical terms reproduce nuclear binding across the chart: a volume term from
  saturation, a surface term from the deficit of edge neighbours, a Coulomb term from
  the electrostatic self-energy of a charged sphere, an asymmetry term from the
  Pauli cost of unequal proton and neutron filling, and a pairing term. The formula
  is quadratic in Z at fixed A, so isobars lie on a mass parabola whose minimum sets
  the most stable charge and whose slope dictates the direction of beta decay. The
  same competition between surface and Coulomb energy defines the fissility parameter
  and the onset of fission.
topics: [Nuclear Properties]
sources:
  - book: Krane
    ref: "Ch. 3 — Nuclear Properties; §3.3 The Semiempirical Mass Formula"
  - book: Wong
    ref: "Ch. 6 — The Liquid Drop Model; §6-1 The Semi-empirical Mass Formula"
  - book: Tipler & Llewellyn
    ref: "Ch. 11 — Nuclear Physics; §11-2 The Liquid-Drop Model"
draft: false
---

The constancy of nuclear density and the near-constant binding energy per nucleon are
the properties of an incompressible charged liquid drop. Weizsäcker turned the analogy
into a formula: write the binding energy as a sum of terms, each with a physical origin
and one fitted coefficient, and the result reproduces the masses of hundreds of nuclides
to about $1\%$.[^krane-semf] This lesson derives each term, assembles the mass parabola,
and extracts the two structural predictions the formula makes without further input: the
most stable isobar and the fissility limit.

## The five terms

> **Theorem (Semi-empirical mass formula).** The binding energy of a nucleus with $Z$
> protons, $N$ neutrons, and $A = Z + N$ is
> $$
> B(Z, A) = a_V A - a_S A^{2/3} - a_C \frac{Z(Z-1)}{A^{1/3}} - a_A \frac{(N-Z)^2}{A} + \delta,
> $$
> and the atomic mass follows from $M(Z, A)c^2 = Z\,M(^1\mathrm{H})c^2 + N\,m_n c^2 - B$.

**Volume term $a_V A$.** Each nucleon interacts only with its nearest neighbours (the
force saturates), so every interior nucleon contributes the same fixed binding. The bulk
energy is therefore proportional to the number of nucleons, and since the volume
$\tfrac43\pi R^3 \propto A$, this is also proportional to volume. Left alone this term
would give a constant $B/A = a_V$; the other terms are corrections that bend the
binding-energy curve.

**Surface term $-a_S A^{2/3}$.** A nucleon at the surface has fewer neighbours than one
in the interior, so it is less bound. The number of surface nucleons scales with the area
$4\pi R^2 \propto A^{2/3}$, and the correction is negative because surface nucleons are
undercounted by the volume term. This is the nuclear surface tension, and it dominates
the light-nucleus rise of $B/A$: small nuclei are nearly all surface.

**Coulomb term $-a_C Z(Z-1)/A^{1/3}$.** The $Z$ protons repel. Treating the charge $Ze$
as a uniformly charged sphere of radius $R = r_0 A^{1/3}$, the electrostatic self-energy
is
$$
E_C = \frac{3}{5}\frac{1}{4\pi\epsilon_0}\frac{(Ze)^2}{R} = \frac{3}{5}\frac{e^2}{4\pi\epsilon_0 r_0}\frac{Z^2}{A^{1/3}}.
$$
Replacing $Z^2$ by $Z(Z-1)$ removes each proton's unphysical self-interaction. The
coefficient is then predicted, not merely fitted:
$$
a_C = \frac{3}{5}\frac{e^2}{4\pi\epsilon_0 r_0} \approx \frac{3}{5}\frac{1.44\ \mathrm{MeV\,fm}}{1.2\ \mathrm{fm}} \approx 0.72\ \mathrm{MeV},
$$
in agreement with the fit. This is the only term that grows with size relative to the
volume, and it is what eventually destabilizes heavy nuclei.

**Asymmetry term $-a_A (N-Z)^2/A$.** Protons and neutrons fill separate ladders of levels
in a shared well, two per level. At fixed $A$ the total kinetic energy is minimized when
the two ladders are filled to the same height, that is $N = Z$. Moving $\nu = (N-Z)/2$
neutrons up from the proton Fermi level into empty neutron levels costs an energy
proportional to the number moved times the level spacing times the shift, all of which
combine to give a cost quadratic in the imbalance and inversely proportional to $A$,
$$
E_{\text{asym}} \sim a_A\frac{(N-Z)^2}{A}.
$$
The full [Fermi-gas derivation](/nuclear-physics/nuclear-models/fermi-gas-model) fixes
the coefficient; here the quadratic form and the $1/A$ suppression are the content. This
term pulls light nuclei toward $N = Z$ and, combined with the Coulomb term, sets the
neutron excess of heavy nuclei.

**Pairing term $\delta$.** Two identical nucleons in the same spatial orbital with paired
spins overlap strongly and bind an extra amount. The correction is
$$
\delta = \begin{cases}
+a_P\,A^{-1/2} & \text{even-}Z,\ \text{even-}N,\\
0 & \text{odd } A,\\
-a_P\,A^{-1/2} & \text{odd-}Z,\ \text{odd-}N,
\end{cases}
$$
with $a_P \approx 12\,\mathrm{MeV}$. Even-even nuclei are the most bound and odd-odd the
least, which is why only four stable odd-odd nuclides exist.

A representative fit gives, in MeV,
$$
a_V \approx 15.8, \quad a_S \approx 17.8, \quad a_C \approx 0.71, \quad a_A \approx 23.7, \quad a_P \approx 12.
$$

$$
% caption: The binding energy per nucleon assembled from the five terms: the constant
% volume term is reduced by the surface term at low A and by the Coulomb term at high A,
% while the asymmetry term subtracts across the range, leaving the observed peaked curve.
\begin{tikzpicture}[>=stealth, font=\footnotesize, scale=1.0]
  \definecolor{acc}{HTML}{4A6FA5}
  \draw[->, black] (0,0) -- (7.8,0) node[right, black!70] {$A$};
  \draw[->, black] (0,0) -- (0,4.6) node[above, black!70] {$\frac{B}{A}$ (MeV)};
  % volume constant
  \draw[black, thick] (0.2,4.1) -- (7.4,4.1);
  \node[black, anchor=west, font=\scriptsize] at (5.4,4.28) {volume $a_V$};
  % minus surface: rises toward a_V
  \draw[black, dashed] (0.2,1.0) .. controls (1.6,3.3) and (3.6,3.85) .. (7.4,4.0);
  \node[black, anchor=west, font=\scriptsize] at (1.9,3.05) {minus surface};
  % minus surface and Coulomb and asymmetry: observed peaked
  \draw[acc, very thick] (0.35,0.6) .. controls (1.5,3.5) and (2.6,3.7) .. (3.0,3.7)
    .. controls (4.6,3.7) and (6.2,2.7) .. (7.4,2.1);
  \node[acc, anchor=west, font=\scriptsize] at (3.15,3.72) {observed $\frac{B}{A}$};
  \node[black, anchor=west, font=\scriptsize] at (5.5,2.5) {minus Coulomb};
\end{tikzpicture}
$$

## The mass parabola at fixed A

Fixing $A$ and writing $N = A - Z$, the atomic mass is a quadratic in $Z$:

$$
M(Z, A)c^2 = \alpha - \beta Z + \gamma Z^2 - \delta,
$$

collecting the $A$-only terms into $\alpha$ and reading off

$$
\gamma = \frac{a_C}{A^{1/3}} + \frac{4 a_A}{A}.
$$

The isobars of a given $A$ lie on this parabola. Its minimum, obtained from
$\partial M/\partial Z = 0$, gives the most stable charge:

$$
Z_A = \frac{4 a_A + (m_n - M(^1\mathrm{H}))c^2}{2\,a_C A^{-1/3} + 8\,a_A A^{-1}}
\approx \frac{A}{1.98 + 0.0155\,A^{2/3}}.
$$

For light nuclei the denominator is near $2$, giving $Z_A \approx A/2$ and $N \approx Z$.
For heavy nuclei the $A^{2/3}$ term (the Coulomb contribution) grows, pushing $Z_A$ below
$A/2$: uranium ($A = 238$) has $Z_A \approx 92$ against $A/2 = 119$, a large neutron
excess. The curve of $Z_A$ against $A$ is the **valley of stability**.

A nuclide displaced from $Z_A$ slides down the parabola by beta decay, which changes $Z$
by one at fixed $A$. On the neutron-rich (low-$Z$) side, $\beta^-$ decay converts a
neutron to a proton and raises $Z$; on the proton-rich (high-$Z$) side, $\beta^+$ decay
or electron capture lowers $Z$. Each step moves toward $Z_A$, and the decay stops at the
isobar nearest the minimum.

$$
% caption: For odd A a single mass parabola holds all isobars; nuclides on the left
% raise Z by electron emission and those on the right lower Z by positron emission or
% capture, both converging on the one stable isobar at the minimum.
\begin{tikzpicture}[>=stealth, font=\footnotesize, scale=1.0]
  \definecolor{acc}{HTML}{4A6FA5}
  \draw[->, black] (0,0) -- (7.4,0) node[right, black!70] {$Z$};
  \draw[->, black] (0,0) -- (0,4.4) node[above, black!70] {mass};
  % parabola
  \draw[acc, very thick] (0.7,4.0) .. controls (2.7,-0.1) and (4.5,-0.1) .. (6.7,4.0);
  % isobar points
  \foreach \x/\y in {1.3/2.85,2.2/1.15,3.05/0.28,3.75/0.28,4.6/1.15,5.5/2.85} \fill[black] (\x,\y) circle (1.9pt);
  % stable minimum highlighted
  \draw[acc, thick] (3.4,0.15) circle (2.6pt);
  \node[black!70, anchor=north, font=\scriptsize] at (3.4,-0.05) {stable};
  % decay direction arrows
  \draw[black, ->] (1.5,2.55) -- (2.0,1.5);
  \draw[black, ->] (2.35,0.95) -- (2.85,0.42);
  \node[black!70, anchor=east, font=\scriptsize, align=right] at (1.9,3.2) {electron\\emission};
  \draw[black, ->] (5.3,2.55) -- (4.8,1.5);
  \draw[black, ->] (4.45,0.95) -- (3.95,0.42);
  \node[black!70, anchor=west, font=\scriptsize, align=left] at (4.9,3.2) {positron\\or capture};
\end{tikzpicture}
$$

## Even-A isobars and double beta decay

For even $A$ the pairing term splits the isobars into two parabolas. Even-even nuclides
(both $Z$ and $N$ even) carry $\delta = +a_P A^{-1/2}$ and lie on the lower curve;
odd-odd nuclides carry $\delta = -a_P A^{-1/2}$ and lie on the upper curve, displaced by
$2\delta \approx 24\,A^{-1/2}\,\mathrm{MeV}$. Successive isobars alternate between the two
parabolas as $Z$ steps by one.

Two consequences follow. First, an even-$A$ chain can have **two or three stable
even-even isobars**, because an even-even nuclide may be unable to reach a lower even-even
neighbour without passing through a higher-lying odd-odd intermediate, which single beta
decay cannot skip. Second, when a would-be single beta decay is energetically forbidden
by the odd-odd hump but the even-even nuclide two steps away lies lower, the transition
can proceed only by **double beta decay**, changing $Z$ by two and emitting two electrons
and two antineutrinos. This second-order weak process, with half-lives beyond
$10^{19}\,\mathrm{yr}$, is the slowest known radioactive decay; its neutrinoless variant
is treated in the
[double beta decay](/nuclear-physics/beta-decay/double-beta-decay-neutrino-mass) lesson.

$$
% caption: For even A the pairing term produces two parabolas, even-even below odd-odd;
% a nuclide trapped on the lower parabola cannot single-beta-decay through the odd-odd
% hump and instead reaches the lower even-even isobar by double beta decay.
\begin{tikzpicture}[>=stealth, font=\footnotesize, scale=1.0]
  \definecolor{acc}{HTML}{4A6FA5}
  \draw[->, black] (0,0) -- (7.4,0) node[right, black!70] {$Z$};
  \draw[->, black] (0,0) -- (0,4.6) node[above, black!70] {mass};
  % even-even parabola (lower)
  \draw[very thick] (0.8,4.1) .. controls (2.7,0.3) and (4.5,0.3) .. (6.6,4.1);
  % odd-odd parabola (upper)
  \draw[black, thick, dashed] (0.95,4.35) .. controls (2.75,1.3) and (4.4,1.3) .. (6.5,4.35);
  % even-even points on lower
  \foreach \x/\y in {1.5/2.65,3.0/0.55,4.5/0.9,6.0/3.1} \fill[black] (\x,\y) circle (1.9pt);
  % odd-odd points on upper
  \foreach \x/\y in {2.25/1.75,3.75/1.45,5.25/2.15} \draw[black, thick] (\x,\y) circle (2.0pt);
  \node[black, anchor=west, font=\scriptsize] at (4.6,0.6) {even-even};
  \node[black, anchor=west, font=\scriptsize] at (5.4,2.35) {odd-odd};
  % double beta arrow skipping the hump
  \draw[acc, ->] (3.0,0.9) .. controls (3.4,1.55) and (4.1,1.55) .. (4.5,1.25);
  \node[acc, anchor=south, font=\scriptsize] at (3.75,1.55) {double beta};
\end{tikzpicture}
$$

## The fissility parameter and the onset of fission

Deform the drop into a prolate ellipsoid at fixed volume, parametrized by a small
elongation $\varepsilon$. The surface area increases while the mean charge separation
grows, so to second order the surface and Coulomb energies shift by

$$
E_S(\varepsilon) = E_S\Bigl(1 + \tfrac25\varepsilon^2\Bigr), \qquad
E_C(\varepsilon) = E_C\Bigl(1 - \tfrac15\varepsilon^2\Bigr),
$$

where $E_S = a_S A^{2/3}$ and $E_C = a_C Z^2/A^{1/3}$ are the spherical values. The net
change in energy is

$$
\Delta E = \frac{\varepsilon^2}{5}\bigl(2 E_S - E_C\bigr).
$$

The sphere is stable against deformation while $\Delta E > 0$, that is while $E_C < 2E_S$.
The stability boundary $E_C = 2E_S$ defines the **fissility parameter**:

$$
x = \frac{E_C}{2 E_S} = \frac{a_C}{2 a_S}\frac{Z^2}{A}
= \frac{Z^2/A}{\left(Z^2/A\right)_{\text{crit}}}, \qquad
\left(\frac{Z^2}{A}\right)_{\text{crit}} = \frac{2 a_S}{a_C} \approx 50.
$$

When $Z^2/A$ approaches $50$ the fission barrier vanishes and the nucleus is unstable to
immediate breakup; the heaviest nuclei ($Z^2/A \approx 36$ for uranium) sit below the
limit but with a barrier low enough that fission competes with alpha decay. The dynamics
of the barrier and the scission path are developed in the
[fission](/nuclear-physics/fission/fission-barrier-dynamics) module.

$$
% caption: The fissility Z-squared over A rises across the chart; the surface energy
% holds the drop spherical until the Coulomb energy exceeds twice the surface energy near
% the critical value fifty, where the barrier against deformation disappears.
\begin{tikzpicture}[>=stealth, font=\footnotesize, scale=1.0]
  \definecolor{acc}{HTML}{4A6FA5}
  \draw[->, black] (0,0) -- (7.6,0) node[right, black!70] {$A$};
  \draw[->, black] (0,0) -- (0,4.4) node[above, black!70] {$\frac{Z^2}{A}$};
  % rising curve of Z^2/A along stability
  \draw[acc, very thick] (0.3,0.5) .. controls (2.6,1.6) and (4.8,2.9) .. (7.2,3.7);
  % critical line at ~50
  \draw[black, dashed] (0,3.9) -- (7.4,3.9);
  \node[black!70, anchor=south east, font=\scriptsize] at (7.3,3.9) {critical value 50};
  % marker for uranium region
  \fill[black] (6.4,3.35) circle (1.9pt);
  \node[black, anchor=north west, font=\scriptsize] at (6.4,3.3) {heavy nuclei};
  % marker for barrier vanishing
  \node[black, anchor=west, font=\scriptsize] at (0.5,4.15) {barrier vanishes above the line};
\end{tikzpicture}
$$

The mass formula is a smooth surface: it captures the bulk trends and the average valley
of stability but has no shell structure, so it misses the extra binding at magic numbers
and cannot predict ground-state spins. Those require the single-particle models, and the
static shape degrees of freedom the drop supplies here become the collective coordinates
of the deformed-nucleus models. The remaining property the drop cannot supply, the
angular momentum and electromagnetic moments of the ground state, is the subject of the
next lesson.

[^krane-semf]: **Krane**, _Introductory Nuclear Physics_, §3.3 (The Semiempirical Mass Formula): the five-term binding-energy expression, representative coefficients, the mass parabola and most-stable-isobar condition, and the surface-versus-Coulomb deformation analysis giving the fissility parameter. The liquid-drop deformation energetics follow **Wong**, _Introductory Nuclear Physics_, §6-1; coefficient fits are calibrated to the evaluated masses at the NNDC, [https://www.nndc.bnl.gov/](https://www.nndc.bnl.gov/).
